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-2/3x-3(x+6)+5=-4
We move all terms to the left:
-2/3x-3(x+6)+5-(-4)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2/3x-3(x+6)+9=0
We multiply parentheses
-2/3x-3x-18+9=0
We multiply all the terms by the denominator
-3x*3x-18*3x+9*3x-2=0
Wy multiply elements
-9x^2-54x+27x-2=0
We add all the numbers together, and all the variables
-9x^2-27x-2=0
a = -9; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·(-9)·(-2)
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3\sqrt{73}}{2*-9}=\frac{27-3\sqrt{73}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3\sqrt{73}}{2*-9}=\frac{27+3\sqrt{73}}{-18} $
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