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-2/3x=5+x
We move all terms to the left:
-2/3x-(5+x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2/3x-(x+5)=0
We get rid of parentheses
-2/3x-x-5=0
We multiply all the terms by the denominator
-x*3x-5*3x-2=0
Wy multiply elements
-3x^2-15x-2=0
a = -3; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·(-3)·(-2)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{201}}{2*-3}=\frac{15-\sqrt{201}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{201}}{2*-3}=\frac{15+\sqrt{201}}{-6} $
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