-2/5(5n-1)=-3/5(n+2)

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Solution for -2/5(5n-1)=-3/5(n+2) equation: 



-2/5(5n-1)=-3/5(n+2)

We move all terms to the left:

-2/5(5n-1)-(-3/5(n+2))=0



Domain of the equation: 5(5n-1)!=0

n∈R





Domain of the equation: 5(n+2))!=0

n∈R



We calculate fractions


(-10nn/(5(5n-1)*5(n+2)))+(-(-15n5)/(5(5n-1)*5(n+2)))=0



We calculate terms in parentheses: +(-10nn/(5(5n-1)*5(n+2))), so:

-10nn/(5(5n-1)*5(n+2))

We multiply all the terms by the denominator


-10nn

Back to the equation:

+(-10nn)





We calculate terms in parentheses: +(-(-15n5)/(5(5n-1)*5(n+2))), so:

-(-15n5)/(5(5n-1)*5(n+2))

We add all the numbers together, and all the variables

-(-15n^5)/(5(5n-1)*5(n+2))

We multiply all the terms by the denominator


-(-15n^5)

We do not support enpression: n^5

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