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-2/5x+3=6/2x-13
We move all terms to the left:
-2/5x+3-(6/2x-13)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x-13)!=0We get rid of parentheses
x∈R
-2/5x-6/2x+13+3=0
We calculate fractions
(-4x)/10x^2+(-30x)/10x^2+13+3=0
We add all the numbers together, and all the variables
(-4x)/10x^2+(-30x)/10x^2+16=0
We multiply all the terms by the denominator
(-4x)+(-30x)+16*10x^2=0
Wy multiply elements
160x^2+(-4x)+(-30x)=0
We get rid of parentheses
160x^2-4x-30x=0
We add all the numbers together, and all the variables
160x^2-34x=0
a = 160; b = -34; c = 0;
Δ = b2-4ac
Δ = -342-4·160·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34}{2*160}=\frac{0}{320} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34}{2*160}=\frac{68}{320} =17/80 $
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