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-2/5x-6=x+1=
We move all terms to the left:
-2/5x-6-(x+1)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-2/5x-x-1-6=0
We multiply all the terms by the denominator
-x*5x-1*5x-6*5x-2=0
Wy multiply elements
-5x^2-5x-30x-2=0
We add all the numbers together, and all the variables
-5x^2-35x-2=0
a = -5; b = -35; c = -2;
Δ = b2-4ac
Δ = -352-4·(-5)·(-2)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1185}}{2*-5}=\frac{35-\sqrt{1185}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1185}}{2*-5}=\frac{35+\sqrt{1185}}{-10} $
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