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-2/5y-1/6y=510
We move all terms to the left:
-2/5y-1/6y-(510)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 6y!=0We calculate fractions
y!=0/6
y!=0
y∈R
(-12y)/30y^2+(-5y)/30y^2-510=0
We multiply all the terms by the denominator
(-12y)+(-5y)-510*30y^2=0
Wy multiply elements
-15300y^2+(-12y)+(-5y)=0
We get rid of parentheses
-15300y^2-12y-5y=0
We add all the numbers together, and all the variables
-15300y^2-17y=0
a = -15300; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·(-15300)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*-15300}=\frac{0}{-30600} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*-15300}=\frac{34}{-30600} =-1/900 $
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