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-2/x+4=2/2x-1
We move all terms to the left:
-2/x+4-(2/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
-2/x-2/2x+1+4=0
We calculate fractions
(-4x)/2x^2+(-2x)/2x^2+1+4=0
We add all the numbers together, and all the variables
(-4x)/2x^2+(-2x)/2x^2+5=0
We multiply all the terms by the denominator
(-4x)+(-2x)+5*2x^2=0
Wy multiply elements
10x^2+(-4x)+(-2x)=0
We get rid of parentheses
10x^2-4x-2x=0
We add all the numbers together, and all the variables
10x^2-6x=0
a = 10; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·10·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*10}=\frac{12}{20} =3/5 $
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