-2/y-4=-6/3y-12+2

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Solution for -2/y-4=-6/3y-12+2 equation: 



-2/y-4=-6/3y-12+2

We move all terms to the left:

-2/y-4-(-6/3y-12+2)=0



Domain of the equation: y!=0

y∈R





Domain of the equation: 3y-12+2)!=0

We move all terms containing y to the left, all other terms to the right

3y+2)!=12

y∈R



We add all the numbers together, and all the variables

-2/y-(-6/3y-10)-4=0

We get rid of parentheses

-2/y+6/3y+10-4=0

We calculate fractions


(-6y)/3y^2+6y/3y^2+10-4=0

We add all the numbers together, and all the variables

(-6y)/3y^2+6y/3y^2+6=0

We multiply all the terms by the denominator


(-6y)+6y+6*3y^2=0

We add all the numbers together, and all the variables

6y+(-6y)+6*3y^2=0

Wy multiply elements

18y^2+6y+(-6y)=0

We get rid of parentheses

18y^2+6y-6y=0

We add all the numbers together, and all the variables

18y^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{36}=0$

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