-20(1-35b)=68(10b+35)

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Solution for -20(1-35b)=68(10b+35) equation: 



-20(1-35b)=68(10b+35)

We move all terms to the left:

-20(1-35b)-(68(10b+35))=0

We add all the numbers together, and all the variables

-20(-35b+1)-(68(10b+35))=0

We multiply parentheses

700b-(68(10b+35))-20=0



We calculate terms in parentheses: -(68(10b+35)), so:

68(10b+35)

We multiply parentheses

680b+2380

Back to the equation:

-(680b+2380)



We get rid of parentheses

700b-680b-2380-20=0

We add all the numbers together, and all the variables

20b-2400=0

We move all terms containing b to the left, all other terms to the right

20b=2400

b=2400/20

b=120

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