-20(x+1)+6(4x-7)=3(x-4)+11

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Solution for -20(x+1)+6(4x-7)=3(x-4)+11 equation: 



-20(x+1)+6(4x-7)=3(x-4)+11

We move all terms to the left:

-20(x+1)+6(4x-7)-(3(x-4)+11)=0

We multiply parentheses

-20x+24x-(3(x-4)+11)-20-42=0



We calculate terms in parentheses: -(3(x-4)+11), so:

3(x-4)+11

We multiply parentheses

3x-12+11

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

4x-(3x-1)-62=0

We get rid of parentheses

4x-3x+1-62=0

We add all the numbers together, and all the variables

x-61=0

We move all terms containing x to the left, all other terms to the right

x=61

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