-20(x-2)+40x=20(x+4)-40

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Solution for -20(x-2)+40x=20(x+4)-40 equation:


Simplifying
-20(x + -2) + 40x = 20(x + 4) + -40

Reorder the terms:
-20(-2 + x) + 40x = 20(x + 4) + -40
(-2 * -20 + x * -20) + 40x = 20(x + 4) + -40
(40 + -20x) + 40x = 20(x + 4) + -40

Combine like terms: -20x + 40x = 20x
40 + 20x = 20(x + 4) + -40

Reorder the terms:
40 + 20x = 20(4 + x) + -40
40 + 20x = (4 * 20 + x * 20) + -40
40 + 20x = (80 + 20x) + -40

Reorder the terms:
40 + 20x = 80 + -40 + 20x

Combine like terms: 80 + -40 = 40
40 + 20x = 40 + 20x

Add '-40' to each side of the equation.
40 + -40 + 20x = 40 + -40 + 20x

Combine like terms: 40 + -40 = 0
0 + 20x = 40 + -40 + 20x
20x = 40 + -40 + 20x

Combine like terms: 40 + -40 = 0
20x = 0 + 20x
20x = 20x

Add '-20x' to each side of the equation.
20x + -20x = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 20x + -20x

Combine like terms: 20x + -20x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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