-20+2y-8=3(y-11)

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Solution for -20+2y-8=3(y-11) equation:



-20+2y-8=3(y-11)
We move all terms to the left:
-20+2y-8-(3(y-11))=0
We add all the numbers together, and all the variables
2y-(3(y-11))-28=0
We calculate terms in parentheses: -(3(y-11)), so:
3(y-11)
We multiply parentheses
3y-33
Back to the equation:
-(3y-33)
We get rid of parentheses
2y-3y+33-28=0
We add all the numbers together, and all the variables
-1y+5=0
We move all terms containing y to the left, all other terms to the right
-y=-5
y=-5/-1
y=+5

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