-20+42z=7(6z-4)+8

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Solution for -20+42z=7(6z-4)+8 equation: 



-20+42z=7(6z-4)+8

We move all terms to the left:

-20+42z-(7(6z-4)+8)=0



We calculate terms in parentheses: -(7(6z-4)+8), so:

7(6z-4)+8

We multiply parentheses

42z-28+8

We add all the numbers together, and all the variables

42z-20

Back to the equation:

-(42z-20)



We get rid of parentheses

42z-42z+20-20=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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