-20-3y=3y+20+20

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Solution for -20-3y=3y+20+20 equation: 



-20-3y=3y+20+20

We move all terms to the left:

-20-3y-(3y+20+20)=0

We add all the numbers together, and all the variables

-3y-(3y+40)-20=0

We get rid of parentheses

-3y-3y-40-20=0

We add all the numbers together, and all the variables

-6y-60=0

We move all terms containing y to the left, all other terms to the right

-6y=60

y=60/-6

y=-10

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