-200=10(3q-10)-20

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Solution for -200=10(3q-10)-20 equation:



-200=10(3q-10)-20
We move all terms to the left:
-200-(10(3q-10)-20)=0
We calculate terms in parentheses: -(10(3q-10)-20), so:
10(3q-10)-20
We multiply parentheses
30q-100-20
We add all the numbers together, and all the variables
30q-120
Back to the equation:
-(30q-120)
We get rid of parentheses
-30q+120-200=0
We add all the numbers together, and all the variables
-30q-80=0
We move all terms containing q to the left, all other terms to the right
-30q=80
q=80/-30
q=-2+2/3

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