-200=30j-5)5j+20

Solution for -200=30j-5)5j+20 equation:

-200=30j-5)5j+20

We move all terms to the left:

-200-(30j-5)5j+20)=0

We add all the numbers together, and all the variables

-(30j-5)5j=0

We multiply parentheses

-150j^2+25j=0

a = -150; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-150)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-150}=\frac{-50}{-300}
=1/6
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-150}=\frac{0}{-300}
=0
$