-20=-8w+6w(w-3)

Solution for -20=-8w+6w(w-3) equation:

-20=-8w+6w(w-3)

We move all terms to the left:

-20-(-8w+6w(w-3))=0


We calculate terms in parentheses: -(-8w+6w(w-3)), so:

-8w+6w(w-3)

We multiply parentheses

6w^2-8w-18w

We add all the numbers together, and all the variables

6w^2-26w

Back to the equation:

-(6w^2-26w)


We get rid of parentheses

-6w^2+26w-20=0

a = -6; b = 26; c = -20;
Δ = b2-4ac
Δ = 262-4·(-6)·(-20)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*-6}=\frac{-40}{-12}
=3+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*-6}=\frac{-12}{-12}
=1
$