-20=2(n-2)

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Solution for -20=2(n-2) equation: 



-20=2(n-2)

We move all terms to the left:

-20-(2(n-2))=0



We calculate terms in parentheses: -(2(n-2)), so:

2(n-2)

We multiply parentheses

2n-4

Back to the equation:

-(2n-4)



We get rid of parentheses

-2n+4-20=0

We add all the numbers together, and all the variables

-2n-16=0

We move all terms containing n to the left, all other terms to the right

-2n=16

n=16/-2

n=-8

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