-20=2(u-3)+5u

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Solution for -20=2(u-3)+5u equation: 



-20=2(u-3)+5u

We move all terms to the left:

-20-(2(u-3)+5u)=0



We calculate terms in parentheses: -(2(u-3)+5u), so:

2(u-3)+5u

We add all the numbers together, and all the variables

5u+2(u-3)

We multiply parentheses

5u+2u-6

We add all the numbers together, and all the variables

7u-6

Back to the equation:

-(7u-6)



We get rid of parentheses

-7u+6-20=0

We add all the numbers together, and all the variables

-7u-14=0

We move all terms containing u to the left, all other terms to the right

-7u=14

u=14/-7

u=-2

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