-20=2(y-4)-8y

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Solution for -20=2(y-4)-8y equation: 



-20=2(y-4)-8y

We move all terms to the left:

-20-(2(y-4)-8y)=0



We calculate terms in parentheses: -(2(y-4)-8y), so:

2(y-4)-8y

We add all the numbers together, and all the variables

-8y+2(y-4)

We multiply parentheses

-8y+2y-8

We add all the numbers together, and all the variables

-6y-8

Back to the equation:

-(-6y-8)



We get rid of parentheses

6y+8-20=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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