-20=2/3(9m+24)

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Solution for -20=2/3(9m+24) equation: 



-20=2/3(9m+24)

We move all terms to the left:

-20-(2/3(9m+24))=0



Domain of the equation: 3(9m+24))!=0

m∈R



We multiply all the terms by the denominator


-(2-20*3(9m+24))=0



We calculate terms in parentheses: -(2-20*3(9m+24)), so:

2-20*3(9m+24)

determiningTheFunctionDomain
-20*3(9m+24)+2

Wy multiply elements

-60m(9+2

Back to the equation:

-(-60m(9+2)



We add all the numbers together, and all the variables

-(-60m11=0

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