-20=2u+6(u+2)

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Solution for -20=2u+6(u+2) equation: 



-20=2u+6(u+2)

We move all terms to the left:

-20-(2u+6(u+2))=0



We calculate terms in parentheses: -(2u+6(u+2)), so:

2u+6(u+2)

We multiply parentheses

2u+6u+12

We add all the numbers together, and all the variables

8u+12

Back to the equation:

-(8u+12)



We get rid of parentheses

-8u-12-20=0

We add all the numbers together, and all the variables

-8u-32=0

We move all terms containing u to the left, all other terms to the right

-8u=32

u=32/-8

u=-4

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