-20x2+20x-5=0

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Solution for -20x2+20x-5=0 equation: 



-20x^2+20x-5=0

a = -20; b = 20; c = -5;
Δ = b2-4ac
Δ = 202-4·(-20)·(-5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-40}=1/2$

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