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-21(2-x)12x=44
We move all terms to the left:
-21(2-x)12x-(44)=0
We add all the numbers together, and all the variables
-21(-1x+2)12x-44=0
We multiply parentheses
252x^2-504x-44=0
a = 252; b = -504; c = -44;
Δ = b2-4ac
Δ = -5042-4·252·(-44)
Δ = 298368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{298368}=\sqrt{576*518}=\sqrt{576}*\sqrt{518}=24\sqrt{518}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-504)-24\sqrt{518}}{2*252}=\frac{504-24\sqrt{518}}{504} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-504)+24\sqrt{518}}{2*252}=\frac{504+24\sqrt{518}}{504} $
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