-21x-5(5-6x)=6(x-4)-13

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Solution for -21x-5(5-6x)=6(x-4)-13 equation:



-21x-5(5-6x)=6(x-4)-13
We move all terms to the left:
-21x-5(5-6x)-(6(x-4)-13)=0
We add all the numbers together, and all the variables
-21x-5(-6x+5)-(6(x-4)-13)=0
We multiply parentheses
-21x+30x-(6(x-4)-13)-25=0
We calculate terms in parentheses: -(6(x-4)-13), so:
6(x-4)-13
We multiply parentheses
6x-24-13
We add all the numbers together, and all the variables
6x-37
Back to the equation:
-(6x-37)
We add all the numbers together, and all the variables
9x-(6x-37)-25=0
We get rid of parentheses
9x-6x+37-25=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4

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