-22+36v=-22(1+22v)

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Solution for -22+36v=-22(1+22v) equation: 



-22+36v=-22(1+22v)

We move all terms to the left:

-22+36v-(-22(1+22v))=0

We add all the numbers together, and all the variables

36v-(-22(22v+1))-22=0



We calculate terms in parentheses: -(-22(22v+1)), so:

-22(22v+1)

We multiply parentheses

-484v-22

Back to the equation:

-(-484v-22)



We get rid of parentheses

36v+484v+22-22=0

We add all the numbers together, and all the variables

520v=0

v=0/520

v=0

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