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-22/5f=(-31/5)
We move all terms to the left:
-22/5f-((-31/5))=0
Domain of the equation: 5f!=0We calculate fractions
f!=0/5
f!=0
f∈R
()/25f^2+(-((-31*5f)/25f^2=0
We multiply all the terms by the denominator
(-((-31*5f)+()=0
We calculate terms in parentheses: +(-((-31*5f)+(), so:
-((-31*5f)+(
We calculate terms in parentheses: +(-((-31*5f)+(), so:
-((-31*5f)+(
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-((-31*5f)+(
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-((-31*5f)+(
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