-22=4y+2(y-3)

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Solution for -22=4y+2(y-3) equation: 



-22=4y+2(y-3)

We move all terms to the left:

-22-(4y+2(y-3))=0



We calculate terms in parentheses: -(4y+2(y-3)), so:

4y+2(y-3)

We multiply parentheses

4y+2y-6

We add all the numbers together, and all the variables

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

-6y+6-22=0

We add all the numbers together, and all the variables

-6y-16=0

We move all terms containing y to the left, all other terms to the right

-6y=16

y=16/-6

y=-2+2/3

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