-22x(x+1=0)

Solution for -22x(x+1=0) equation:

-22x(x+1=0)

We move all terms to the left:

-22x(x+1-(0))=0

We add all the numbers together, and all the variables

-22x(x+1)=0

We multiply parentheses

-22x^2-22x=0

a = -22; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·(-22)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*-22}=\frac{0}{-44}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*-22}=\frac{44}{-44}
=-1
$