-22x-12=4(5x-3)+6

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Solution for -22x-12=4(5x-3)+6 equation: 



-22x-12=4(5x-3)+6

We move all terms to the left:

-22x-12-(4(5x-3)+6)=0



We calculate terms in parentheses: -(4(5x-3)+6), so:

4(5x-3)+6

We multiply parentheses

20x-12+6

We add all the numbers together, and all the variables

20x-6

Back to the equation:

-(20x-6)



We get rid of parentheses

-22x-20x+6-12=0

We add all the numbers together, and all the variables

-42x-6=0

We move all terms containing x to the left, all other terms to the right

-42x=6

x=6/-42

x=-1/7

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