-23x2+92=0

Solution for -23x2+92=0 equation:

-23x^2+92=0

a = -23; b = 0; c = +92;
Δ = b2-4ac
Δ = 02-4·(-23)·92
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-92}{2*-23}=\frac{-92}{-46}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+92}{2*-23}=\frac{92}{-46}
=-2
$