-24+12d=2(d-6)+22

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Solution for -24+12d=2(d-6)+22 equation: 



-24+12d=2(d-6)+22

We move all terms to the left:

-24+12d-(2(d-6)+22)=0



We calculate terms in parentheses: -(2(d-6)+22), so:

2(d-6)+22

We multiply parentheses

2d-12+22

We add all the numbers together, and all the variables

2d+10

Back to the equation:

-(2d+10)



We get rid of parentheses

12d-2d-10-24=0

We add all the numbers together, and all the variables

10d-34=0

We move all terms containing d to the left, all other terms to the right

10d=34

d=34/10

d=3+2/5

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