-24-(2/3)j=16

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Solution for -24-(2/3)j=16 equation: 



-24-(2/3)j=16

We move all terms to the left:

-24-(2/3)j-(16)=0



Domain of the equation: 3)j!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

-(+2/3)j-24-16=0

We add all the numbers together, and all the variables

-(+2/3)j-40=0

We multiply parentheses

-2j^2-40=0

a = -2; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·(-2)·(-40)
Δ = -320
Delta is less than zero, so there is no solution for the equation

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