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-24=2(y-3)/5y
We move all terms to the left:
-24-(2(y-3)/5y)=0
Domain of the equation: 5y)!=0We multiply all the terms by the denominator
y!=0/1
y!=0
y∈R
-(2(y-3)-24*5y)=0
We calculate terms in parentheses: -(2(y-3)-24*5y), so:We get rid of parentheses
2(y-3)-24*5y
We multiply parentheses
2y-24*5y-6
Wy multiply elements
2y-120y-6
We add all the numbers together, and all the variables
-118y-6
Back to the equation:
-(-118y-6)
118y+6=0
We move all terms containing y to the left, all other terms to the right
118y=-6
y=-6/118
y=-3/59
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