-24x-12=2(x-3)+22

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Solution for -24x-12=2(x-3)+22 equation: 



-24x-12=2(x-3)+22

We move all terms to the left:

-24x-12-(2(x-3)+22)=0



We calculate terms in parentheses: -(2(x-3)+22), so:

2(x-3)+22

We multiply parentheses

2x-6+22

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

-24x-2x-16-12=0

We add all the numbers together, and all the variables

-26x-28=0

We move all terms containing x to the left, all other terms to the right

-26x=28

x=28/-26

x=-1+1/13

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