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-24x^2-45x+6=0
a = -24; b = -45; c = +6;
Δ = b2-4ac
Δ = -452-4·(-24)·6
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-51}{2*-24}=\frac{-6}{-48} =1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+51}{2*-24}=\frac{96}{-48} =-2 $
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