-25-(3y+1)=3(y-2)+4y

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Solution for -25-(3y+1)=3(y-2)+4y equation: 



-25-(3y+1)=3(y-2)+4y

We move all terms to the left:

-25-(3y+1)-(3(y-2)+4y)=0

We get rid of parentheses

-3y-(3(y-2)+4y)-1-25=0



We calculate terms in parentheses: -(3(y-2)+4y), so:

3(y-2)+4y

We add all the numbers together, and all the variables

4y+3(y-2)

We multiply parentheses

4y+3y-6

We add all the numbers together, and all the variables

7y-6

Back to the equation:

-(7y-6)



We add all the numbers together, and all the variables

-3y-(7y-6)-26=0

We get rid of parentheses

-3y-7y+6-26=0

We add all the numbers together, and all the variables

-10y-20=0

We move all terms containing y to the left, all other terms to the right

-10y=20

y=20/-10

y=-2

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