-25=1/2(10r-2)-3

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Solution for -25=1/2(10r-2)-3 equation: 



-25=1/2(10r-2)-3

We move all terms to the left:

-25-(1/2(10r-2)-3)=0



Domain of the equation: 2(10r-2)-3)!=0

r∈R



We multiply all the terms by the denominator


-(1-25*2(10r-2)-3)=0



We calculate terms in parentheses: -(1-25*2(10r-2)-3), so:

1-25*2(10r-2)-3

determiningTheFunctionDomain
-25*2(10r-2)+1-3

We add all the numbers together, and all the variables

-25*2(10r-2)-2

Wy multiply elements

-50r(1-2

Back to the equation:

-(-50r(1-2)



We add all the numbers together, and all the variables

-(-50r(-1)=0



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-50r(-1





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