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-25=1/2(10x-2)+3x
We move all terms to the left:
-25-(1/2(10x-2)+3x)=0
Domain of the equation: 2(10x-2)+3x)!=0We multiply all the terms by the denominator
x∈R
-(1-25*2(10x-2)+3x)=0
We calculate terms in parentheses: -(1-25*2(10x-2)+3x), so:We add all the numbers together, and all the variables
1-25*2(10x-2)+3x
determiningTheFunctionDomain -25*2(10x-2)+3x+1
We add all the numbers together, and all the variables
3x-25*2(10x-2)+1
Wy multiply elements
3x-50x(1+1
Back to the equation:
-(3x-50x(1+1)
-(3x-50x2=0
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