-25=5/2(8r-6)+2r=32

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Solution for -25=5/2(8r-6)+2r=32 equation: 



-25=5/2(8r-6)+2r=32

We move all terms to the left:

-25-(5/2(8r-6)+2r)=0



Domain of the equation: 2(8r-6)+2r)!=0

r∈R



We multiply all the terms by the denominator


-(5-25*2(8r-6)+2r)=0



We calculate terms in parentheses: -(5-25*2(8r-6)+2r), so:

5-25*2(8r-6)+2r

determiningTheFunctionDomain
-25*2(8r-6)+2r+5

We add all the numbers together, and all the variables

2r-25*2(8r-6)+5

Wy multiply elements

2r-50r(8+5

Back to the equation:

-(2r-50r(8+5)



We add all the numbers together, and all the variables

-(2r-50r13=0

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