-26(x-2)+3x=12

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Solution for -26(x-2)+3x=12 equation: 



-26(x-2)+3x=12

We move all terms to the left:

-26(x-2)+3x-(12)=0

We add all the numbers together, and all the variables

3x-26(x-2)-12=0

We multiply parentheses

3x-26x+52-12=0

We add all the numbers together, and all the variables

-23x+40=0

We move all terms containing x to the left, all other terms to the right

-23x=-40

x=-40/-23

x=1+17/23

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