-26+2b=4(b-3)

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Solution for -26+2b=4(b-3) equation: 



-26+2b=4(b-3)

We move all terms to the left:

-26+2b-(4(b-3))=0



We calculate terms in parentheses: -(4(b-3)), so:

4(b-3)

We multiply parentheses

4b-12

Back to the equation:

-(4b-12)



We get rid of parentheses

2b-4b+12-26=0

We add all the numbers together, and all the variables

-2b-14=0

We move all terms containing b to the left, all other terms to the right

-2b=14

b=14/-2

b=-7

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