-26-6=2x-4x(x-1)

Solution for -26-6=2x-4x(x-1) equation:

-26-6=2x-4x(x-1)

We move all terms to the left:

-26-6-(2x-4x(x-1))=0

We add all the numbers together, and all the variables

-(2x-4x(x-1))-32=0


We calculate terms in parentheses: -(2x-4x(x-1)), so:

2x-4x(x-1)

We multiply parentheses

-4x^2+2x+4x

We add all the numbers together, and all the variables

-4x^2+6x

Back to the equation:

-(-4x^2+6x)


We get rid of parentheses

4x^2-6x-32=0

a = 4; b = -6; c = -32;
Δ = b2-4ac
Δ = -62-4·4·(-32)
Δ = 548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{548}=\sqrt{4*137}=\sqrt{4}*\sqrt{137}=2\sqrt{137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{137}}{2*4}=\frac{6-2\sqrt{137}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{137}}{2*4}=\frac{6+2\sqrt{137}}{8}
$