-26/5k+3/2k=-37/20

Solution for -26/5k+3/2k=-37/20 equation:

-26/5k+3/2k=-37/20

We move all terms to the left:

-26/5k+3/2k-(-37/20)=0


Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R



Domain of the equation: 2k!=0

k!=0/2

k!=0

k∈R


We get rid of parentheses

-26/5k+3/2k+37/20=0

We calculate fractions


740k^2/400k^2+(-2080k)/400k^2+600k/400k^2=0

We multiply all the terms by the denominator


740k^2+(-2080k)+600k=0

We add all the numbers together, and all the variables

740k^2+600k+(-2080k)=0

We get rid of parentheses

740k^2+600k-2080k=0

We add all the numbers together, and all the variables

740k^2-1480k=0

a = 740; b = -1480; c = 0;
Δ = b2-4ac
Δ = -14802-4·740·0
Δ = 2190400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2190400}=1480$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1480)-1480}{2*740}=\frac{0}{1480}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1480)+1480}{2*740}=\frac{2960}{1480}
=2
$