-26=3(v-2)-5v

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Solution for -26=3(v-2)-5v equation: 



-26=3(v-2)-5v

We move all terms to the left:

-26-(3(v-2)-5v)=0



We calculate terms in parentheses: -(3(v-2)-5v), so:

3(v-2)-5v

We add all the numbers together, and all the variables

-5v+3(v-2)

We multiply parentheses

-5v+3v-6

We add all the numbers together, and all the variables

-2v-6

Back to the equation:

-(-2v-6)



We get rid of parentheses

2v+6-26=0

We add all the numbers together, and all the variables

2v-20=0

We move all terms containing v to the left, all other terms to the right

2v=20

v=20/2

v=10

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