-26t2+755t-150=0

Solution for -26t2+755t-150=0 equation:

-26t^2+755t-150=0

a = -26; b = 755; c = -150;
Δ = b2-4ac
Δ = 7552-4·(-26)·(-150)
Δ = 554425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{554425}=\sqrt{25*22177}=\sqrt{25}*\sqrt{22177}=5\sqrt{22177}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(755)-5\sqrt{22177}}{2*-26}=\frac{-755-5\sqrt{22177}}{-52}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(755)+5\sqrt{22177}}{2*-26}=\frac{-755+5\sqrt{22177}}{-52}
$