-27-(5x-12)=5/2(6-2x)

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Solution for -27-(5x-12)=5/2(6-2x) equation:



-27-(5x-12)=5/2(6-2x)
We move all terms to the left:
-27-(5x-12)-(5/2(6-2x))=0
Domain of the equation: 2(6-2x))!=0
x∈R
We add all the numbers together, and all the variables
-(5x-12)-(5/2(-2x+6))-27=0
We get rid of parentheses
-5x-(5/2(-2x+6))+12-27=0
We multiply all the terms by the denominator
-5x*2(-2x+6))-(5+12*2(-2x+6))-27*2(-2x+6))=0
We add all the numbers together, and all the variables
-2x-5x*2(-2x+6))-(5+12*2(-2x+6))-27*2(=0
Wy multiply elements
-10x^2(-+48x^2(--2x=0
We use the square of the difference formula
-10x^2(-48x^2(+2x=0

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