-27=2(u-3)-5u

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Solution for -27=2(u-3)-5u equation: 



-27=2(u-3)-5u

We move all terms to the left:

-27-(2(u-3)-5u)=0



We calculate terms in parentheses: -(2(u-3)-5u), so:

2(u-3)-5u

We add all the numbers together, and all the variables

-5u+2(u-3)

We multiply parentheses

-5u+2u-6

We add all the numbers together, and all the variables

-3u-6

Back to the equation:

-(-3u-6)



We get rid of parentheses

3u+6-27=0

We add all the numbers together, and all the variables

3u-21=0

We move all terms containing u to the left, all other terms to the right

3u=21

u=21/3

u=7

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