-27z-48=2z+27

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Solution for -27z-48=2z+27 equation: 



-27z-48=2z+27

We move all terms to the left:

-27z-48-(2z+27)=0

We get rid of parentheses

-27z-2z-27-48=0

We add all the numbers together, and all the variables

-29z-75=0

We move all terms containing z to the left, all other terms to the right

-29z=75

z=75/-29

z=-2+17/29

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