-28+3b=-1+3(2b-2)

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Solution for -28+3b=-1+3(2b-2) equation: 



-28+3b=-1+3(2b-2)

We move all terms to the left:

-28+3b-(-1+3(2b-2))=0



We calculate terms in parentheses: -(-1+3(2b-2)), so:

-1+3(2b-2)

determiningTheFunctionDomain
3(2b-2)-1

We multiply parentheses

6b-6-1

We add all the numbers together, and all the variables

6b-7

Back to the equation:

-(6b-7)



We get rid of parentheses

3b-6b+7-28=0

We add all the numbers together, and all the variables

-3b-21=0

We move all terms containing b to the left, all other terms to the right

-3b=21

b=21/-3

b=-7

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